help for query

Hello,
I have a table "log" with the following fields:

-log_id(int)
-cust_id(string)
-type(int)
-service_id(int)

type may be 0,1 or 10

I need to fetch one row for each type for each service_id for a specific
cust_id.
That is, if I have 3 different service_id's and I assume that at least
one row for each type exists with the specific cust_id, I should get 3*3
= 9 rows: no more, no less.
I prefer not to use a stored procedure.
How may I do?
Is a self-join the right way?

Thank you
Regards

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elimina carraro per rispondere via emailYou don't appear to have any criteria for
the one row you want if there are more than one.
If that's the case and log_id is unique, this should work

select max(log_id),cust_id,type,service_id
from log
group by cust_id,type,service_id|||markc600@.hotmail.com ha scritto:
> You don't appear to have any criteria for
> the one row you want if there are more than one.
> If that's the case and log_id is unique, this should work
> select max(log_id),cust_id,type,service_id
> from log
> group by cust_id,type,service_id

It work great, thanks!

I got the same result with the following, but was much more complicated:

select *
from log a, log b
where a.cust_id='myid' and a.type IN (0,10,1) and a.log_id=b.log_id
and b.log_id IN (select top 1 log_id from log c where
c.service_id=a.service_id and c.type=a.type)
order by a.service_id

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elimina carraro per rispondere via email